Read comma-separated numbers

Context

Let's have an input like '12,34,56,78,9,100'. The goal is to have an array of numbers [12], [34], ... in memory, reading comma-separated decimal numbers. To achieve it, we'll have to

• Read a char
• If it's a comma (ASCII code 44), then start a new number
• Otherwise it's a digit, add it to ten times the current number

Note: this post is strongly related to array definition and read decimal number ones

Initial state

• Memory: 0, 0, 0, 0...
• Cursor: first cell
• Input: comma-separated decimal numbers (A,B,C,...)

Process

• Leave one cell to delimit array, plus one cell for current first integer read
• While a character is read
• Remove 44 (',' ASCII code)
• Set else bit
• If result is not null
• It's a digit. Remove 4 to get the decimal digit value
• Update current integer
• Otherwise
• Start a new integer 

Code 

>>
array delimiter and first integer (currently 0)
,[
  >++++[-<----------->]+<
  remove 44 (comma ASCII code) and set bit else
  [>-<
    if read value is not 44 => it is a digit
    ----
    remove 4 again (to remove 48 which is 0's ASCII code)
    >+++++++++[-<<[->+>>+<<<]>>>[-<<<+>>>]<]<[-<+>]
    multiply current integer by ten and add new digit
  ]
  >[-
    else
    >
    move to next integer
  ]<
,]

Code (minified)

>>,[>++++[-<----------->]+<[>-<---->+++++++++[-<<[->+>>+<<<]>>>[-<<<+>>>]<]<[-<+>]]>[->]<,]

Final state

• Memory: 0,A,B,C,...,0
• Cursor: on final 0 (end of array)
• Input: empty
• Output: unchanged

Example

Live 'Comma-separated decimal to ASCII' converter: type comma-separated ASCII code to display the corresponding string (e.g. input 50,48,49,55 produces 2017)